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Metamath Proof Explorer

Theorem ancld

Description: Deduction conjoining antecedent to left of consequent in nested implication. (Contributed by NM, 15-Aug-1994) (Proof shortened by Wolf Lammen, 1-Nov-2012)

		Ref	Expression
	Hypothesis	ancld.1	\|- ( ph -> ( ps -> ch ) )
	Assertion	ancld	\|- ( ph -> ( ps -> ( ps /\ ch ) ) )

Proof

Step	Hyp	Ref	Expression
1		ancld.1	\|- ( ph -> ( ps -> ch ) )
2		idd	\|- ( ph -> ( ps -> ps ) )
3	2 1	jcad	\|- ( ph -> ( ps -> ( ps /\ ch ) ) )