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Metamath Proof Explorer

Theorem 1p0e1

Description: 1 + 0 = 1. (Contributed by David A. Wheeler, 8-Dec-2018)

Ref Expression
Assertion 1p0e1 
|- ( 1 + 0 ) = 1

Proof

Step Hyp Ref Expression
1 ax-1cn 
 |-  1 e. CC
2 1 addridi 
 |-  ( 1 + 0 ) = 1